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प्रश्न
Integrate the following functions with respect to x:
`1/(2 - 3x)^4`
उत्तर
`int ("a"x + "b")^"n" "d"x = 1/"a" ("a"x + "b")^("n" + 1)/("n" + 1) + "c"`
`int 1/(2 - 3x)^4 "d"x = int (2 - 3x)^-4 * "d"x`
= `1/(-3) (2 - 3x)^(-4 + 1)/(-4 + 1) + "c"`
= `1/(-3) (2 - 3x)^-3/(-3) + "c"`
= `1/9 xx 1/(2 - 3x)^3 + "c"`
= `1/(9(2 - 3x)^3 + "c"`
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