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प्रश्न
Integrate the following functions with respect to x:
`sqrt(3x + 2)`
उत्तर
`int("a"x + "b")^"n" "d"x = int(3x + 2)^(1/2) * "d"x`
= `1/3 (3x + 2)^(1/2 + 1)/(1/2 + 1) + "c"`
= `1/3 (3x + 2)^(3/2)/(3/2) + "c"`
= `1/3 xx 2/3 (3x + 2)^(3/2) + "c"`
= `2/9 (3x + 2)^(3/2) + "c"`
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