Advertisements
Advertisements
प्रश्न
Integrate the following functions with respect to x:
`1/(2 - 3x)^4`
उत्तर
`int ("a"x + "b")^"n" "d"x = 1/"a" ("a"x + "b")^("n" + 1)/("n" + 1) + "c"`
`int 1/(2 - 3x)^4 "d"x = int (2 - 3x)^-4 * "d"x`
= `1/(-3) (2 - 3x)^(-4 + 1)/(-4 + 1) + "c"`
= `1/(-3) (2 - 3x)^-3/(-3) + "c"`
= `1/9 xx 1/(2 - 3x)^3 + "c"`
= `1/(9(2 - 3x)^3 + "c"`
APPEARS IN
संबंधित प्रश्न
Integrate the following functions with respect to x:
(x + 5)6
Integrate the following functions with respect to x:
`sqrt(3x + 2)`
Integrate the following functions with respect to x:
sin 3x
Integrate the following functions with respect to x:
cos(5 – 11x)
Integrate the following functions with respect to x:
cosec2 (5x – 7)
Integrate the following functions with respect to x:
`"e"^(3x - 6)`
Integrate the following functions with respect to x:
`"e"^(8 - 7x)`
Integrate the following functions with respect to x:
`1/(6 - 4x)`
Integrate the following functions with respect to x:
`sec^2 x/5`
Integrate the following functions with respect to x:
cosec(5x + 3) cot(5x + 3)
Integrate the following functions with respect to x:
30 sec(2 – 15x) tan(2 – 15x)
Integrate the following functions with respect to x:
`1/sqrt(1 - (4x)^2`
Integrate the following functions with respect to x:
`1/sqrt(1 - 81x^2)`
Integrate the following functions with respect to x:
`1/sqrt(1 + 36x^2)`
Choose the correct alternative:
If `int f"'"(x)"e"^(x^2) "d"x = (x - 1)"e"^(x^2) + "c"`, then`f(x)` is
