Advertisements
Advertisements
प्रश्न
Is 402 a term of the sequence:
8, 13, 18, 23, ................. ?
उत्तर
The given sequence is 8, 13, 18, 23, .................
Now,
13 – 8 = 5
18 – 13 = 5
23 – 18 = 5, etc.
Hence, the given sequence is an A.P. with first term a = 8 and common difference d = 5.
The general term of an A.P. is given by
tn = a + (n – 1)d
`=>` 402 = 8 + (n – 1)(5)
`=>` 394 = 5n – 5
`=>` 399 = 5n
`=> n = 399/5`
The number of terms cannot be a fraction.
So clearly, 402 is not the term of the given sequence.
APPEARS IN
संबंधित प्रश्न
If tn represents nth term of an A.P., t2 + t5 – t3 = 10 and t2 + t9 = 17, find its first term and its common difference.
In an A.P., ten times of its tenth term is equal to thirty times of its 30th term. Find its 40th term.
How many three-digit numbers are divisible by 87?
Determine the value of k for which k2 + 4k + 8, 2k2 + 3k + 6 and 3k2 + 4k + 4 are in A.P.
Which term of A.P 3, 10, 17, .... Will be 84 more than its 13th term?
For the following A.P.s, write the first term a and the common difference d: `(1)/(3), (5)/(3),(9)/(3),(13)/(3)`,...
Write first four terms of the A.P., when the first term a and the common difference d are given as follows : `"a" = (1)/(2), "d" = -(1)/(6)`
The 7th term of the given Arithmetic Progression (A.P.):
`1/a, (1/a + 1), (1/a + 2)`... is:
The first term and the common difference of an A.P. are 8 and –5 respectively. The A.P. is ______.
The 15th term of the A.P. 3, 0, –3, –6, ........ is ______.