Advertisements
Advertisements
प्रश्न
Let f(x) be a polynomial such that \[f\left( - \frac{1}{2} \right)\] = 0, then a factor of f(x) is
विकल्प
2x − 1
2x + 1
x − 1
x +1
उत्तर
Let f(x) be a polynomial such that `f(-1/2) = 0`
i.e., `x + 1/2 = 0` is a factor.
On rearranging `x+ 1/2 = 0` can be written as (2x + 1) = 0
Thus, (2x + 1)is a factor of f(x).
APPEARS IN
संबंधित प्रश्न
Write the coefficient of x2 in the following:
`pi/6x^2- 3x+4`
Identify polynomials in the following:
`h(x)=x^4-x^(3/2)+x-1`
Find the integral roots of the polynomial f(x) = x3 + 6x2 + 11x + 6.
f(x) = 4x3 − 12x2 + 14x − 3, g(x) 2x − 1
Show that (x + 4) , (x − 3) and (x − 7) are factors of x3 − 6x2 − 19x + 84
Using factor theorem, factorize each of the following polynomials:
x3 + 6x2 + 11x + 6
x3 + 2x2 − x − 2
Define zero or root of a polynomial.
One factor of x4 + x2 − 20 is x2 + 5. The other factor is
Factorise:
x3 + x2 – 4x – 4
