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प्रश्न
Match species given in Column I with the electronic configuration given in Column II.
| Column I | Column II |
| (i) \[\ce{Cr}\] | (a) [Ar]3d84s0 |
| (ii) \[\ce{Fe^{2+}}\] | (b) [Ar]3d104s1 |
| (iii) \[\ce{Ni^{2+}}\] | (c) [Ar]3d64s0 |
| (iv) \[\ce{Cu}\] | (d) [Ar] 3d54s1 |
| (e) [Ar]3d64s2 |
उत्तर
| Column I | Column II |
| (i) \[\ce{Cr}\] | (d) [Ar] 3d54s1 |
| (ii) \[\ce{Fe^{2+}}\] | (c) [Ar]3d64s0 |
| (iii) \[\ce{Ni^{2+}}\] | (a) [Ar]3d84s0 |
| (iv) \[\ce{Cu}\] | (b) [Ar]3d104s1 |
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संबंधित प्रश्न
Give the names of quantum numbers.
Write orbital notations for the electron in orbitals with the following quantum numbers.
n = 4, l = 2
Write condensed orbital notation of electronic configuration of the following element:
Lithium (Z = 3)
Write condensed orbital notation of electronic configuration of the following element:
Oxygen (Z = 8)
Draw shapes of 2s orbitals.
Indicate the number of unpaired electrons in \[\ce{Si}\] (Z = 14).
How many electrons can fit in the orbital for which n = 4 and l = 2?
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, solve the questions given below:
Which of the following orbitals has the lowest energy?
5p, 5d, 5f, 6s, 6p
Match the quantum numbers with the information provided by these.
| Quantum number | Information provided |
| (i) Principal quantum number | (a) orientation of the orbital |
| (ii) Azimuthal quantum number | (b) energy and size of orbital |
| (iii) Magnetic quantum number | (c) spin of electron |
| (iv) Spin quantum number | (d) shape of the orbital |
Which of the following is the correct plot for the probability density ψ2 (r) as a function of distance 'r' of the electron from the nucleus for 2s orbitals?
