Advertisements
Advertisements
प्रश्न
Numerical Problem.
A stone weighs 500 N. Calculate the pressure exerted by it if it makes contact with a surface of area 25 cm2.
उत्तर
Given : Weight of a stone F = 500 No
Area A = 25 cm2 = 25 x 10-4 m2
To find : Pressure P = ?
Formula :
Pressure P = `F/A`
= `500/25xx10`-4
Solution: Pressure P = 20 x 104N/m2 (or) 20 x 104 Pa
APPEARS IN
संबंधित प्रश्न
Define the angle of contact.
Explain why Water with detergent dissolved in it should have small angles of contact.
The free surface of a liquid resting in an inertial frame is horizontal. Does the normal to the free surface pass through the centre of the earth? Think separately if the liquid is (a) at the equator (b) at a pole (c) somewhere else.
The force of surface tension acts tangentially to the surface whereas the force due to air pressure acts perpendicularly on the surface. How is then the force due to excess pressure inside a bubble balanced by the force due to the surface tension?
A capillary tube of radius 1 mm is kept vertical with the lower end in water. (a) Find the height of water raised in the capillary. (b) If the length of the capillary tube is half the answer of part , find the angle θ made by the water surface in the capillary with the wall.
Calculate the rise of water inside a clean glass capillary tube of radius 0.1 mm, when immersed in water of surface tension 7 × 10-2 N/m. The angle of contact between water and glass is zero, the density of water = 1000 kg/m3, g = 9.8 m/s2.
Twenty-seven droplets of water, each of radius 0.1 mm coalesce into a single drop. Find the change in surface energy. Surface tension of water is 0.072 N/m.
Insect moves over the surface of water because of ______.
What are the factors affecting the surface tension of a liquid?
A molecule of water on the surface experiences a net ______.