Advertisements
Advertisements
Question
Numerical Problem.
A stone weighs 500 N. Calculate the pressure exerted by it if it makes contact with a surface of area 25 cm2.
Solution
Given : Weight of a stone F = 500 No
Area A = 25 cm2 = 25 x 10-4 m2
To find : Pressure P = ?
Formula :
Pressure P = `F/A`
= `500/25xx10`-4
Solution: Pressure P = 20 x 104N/m2 (or) 20 x 104 Pa
APPEARS IN
RELATED QUESTIONS
Angle of contact for the pair of pure water with clean glass is _______.
Explain why Water with detergent dissolved in it should have small angles of contact.
Fill in the blanks using the word(s) from the list appended with each statement
Surface tension of liquids generally . . . with temperatures (increases / decreases)
Find the surface energy of water kept in a cylindrical vessel of radius 6.0 cm. Surface tension of water = 0.075 J m−2.
Consider an ice cube of edge 1.0 cm kept in a gravity-free hall. Find the surface area of the water when the ice melts. Neglect the difference in densities of ice and water.
Two soap bubbles have a radius in the ratio of 2:3. Compare the works done in blowing these bubbles.
What is capillarity?
Water rises in a capillary tube of radius r upto a height h. The mass of water in a capillary is m. The mass of water that will rise in a capillary of radius `"r"/4` will be ______.
The excess of pressure, due to surface tension, on a spherical liquid drop of radius 'R' is proportional to ______.
Two narrow bores of diameter 5.0 mm and 8.0 mm are joined together to form a U-shaped tube open at both ends. If this U-tube contains water, what is the difference in the level of the two limbs, of the tube?
[Take surface tension of water T = 7.3 × 10-2 Nm-1, angle of contact = 0, g = 10 ms-2 and density of water = 1.0 × 103 kgm-3]
