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On Dividing `3x^3 + X^2 + 2x + 5` is Divided by a Polynomial G(X), the Quotient and Remainder Are (3x – 5) and (9x + 10) Respectively. Find G(X). - Mathematics

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प्रश्न

On dividing `3x^3 + x^2 + 2x + 5` is divided by a polynomial g(x), the quotient and remainder are (3x – 5) and (9x + 10) respectively. Find g(x). 

उत्तर

By using division rule, we have
Dividend = Quotient × Divisor + Remainder 

∴` 3x^3 + x^2 + 2x + 5 = (3x – 5)g(x) + 9x + 10`
⇒`3x^3 + x^2 + 2x + 5 – 9x – 10 = (3x – 5)g(x)`
⇒`3x^3 + x^2 – 7x – 5 = (3x – 5)g(x)` 

⇒ `(g(x)=3x^3+x^2-7x-5)/(3x-5)`  

 

  

`∴g(x) = x^2 + 2x + 1` 

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अध्याय 2: Polynomials - Exercises 2

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आरएस अग्रवाल Mathematics [English] Class 10
अध्याय 2 Polynomials
Exercises 2 | Q 10

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