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प्रश्न
Predict the shapes of the following molecules on the basis of hybridisation.
\[\ce{BCl3, CH4 , CO2, NH3}\]
उत्तर
In \[\ce{BCl3}\], the geometry is trigonal planar is due to sp2 hybridisation.
The shape of \[\ce{CH4}\] is tetrahedral due to sp3 hybridisation.
\[\ce{CO2}\] show linear shape because of sp hybridisation.
The geometry of \[\ce{NH3}\] is pyramidal shape and has sp3 hybridisation.
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संबंधित प्रश्न
Draw a diagram showing the formation of a double bond and a triple bond between carbon atoms in C2H4 and C2H2 molecules.
What is the total number of sigma and pi bonds in the following molecules?
C2H2
What is the total number of sigma and pi bonds in the following molecules?
C2H4
The types of hybrid orbitals of nitrogen in \[\ce{NO^{+}2}\] , \[\ce{NO^{-}3}\] and \[\ce{NH^{+}4}\] respectively are expected to be ______.
Match the species in Column I with the type of hybrid orbitals in Column II.
| Column I | Column II |
| (i) \[\ce{SF4}\] | (a) sp3d2 |
| (ii) \[\ce{IF5}\] | (b) d2sp3 |
| (iii) \[\ce{NO^{+}2}\], | (c) sp3d |
| (iv) \[\ce{NH^{+}4}\], | (d) sp3 |
| (e) sp |
What is the type of hybridisation of carbon atoms marked with star.
\[\begin{array}{cc}
\phantom{.....}\ce{O}\\
\phantom{.....}||\\
\ce{\overset{∗}{C}H2 = CH - \overset{∗}{C} - O - H}
\end{array}\]
What is the type of hybridisation of carbon atoms marked with star.
\[\begin{array}{cc}
\phantom{..........}\ce{O}\\
\phantom{..........}||\\
\ce{CH3 - CH2 - \overset{∗}{C} - H}
\end{array}\]
What is the type of hybridisation of carbon atoms marked with star.
\[\ce{\overset{∗}{C}H3 - CH = CH - CH3}\]
In the given reaction,
the number of sp2 hybridised carbon (s) in compound 'X' is ______.
The hybridisation of carbanion is:
