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Question
Predict the shapes of the following molecules on the basis of hybridisation.
\[\ce{BCl3, CH4 , CO2, NH3}\]
Solution
In \[\ce{BCl3}\], the geometry is trigonal planar is due to sp2 hybridisation.
The shape of \[\ce{CH4}\] is tetrahedral due to sp3 hybridisation.
\[\ce{CO2}\] show linear shape because of sp hybridisation.
The geometry of \[\ce{NH3}\] is pyramidal shape and has sp3 hybridisation.
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| Column I | Column II |
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\[\begin{array}{cc}
\phantom{.....}\ce{O}\\
\phantom{.....}||\\
\ce{\overset{∗}{C}H2 = CH - \overset{∗}{C} - O - H}
\end{array}\]
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\[\ce{CH3 - \overset{∗}{C} ≡ CH}\]
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