Advertisements
Advertisements
प्रश्न
Prove taht the points (-2 , 1) , (-1 , 4) and (0 , 3) are the vertices of a right - angled triangle.
उत्तर
AB = `sqrt ((-2-0)^2 + (1-3)^2) = sqrt (4 + 4) = sqrt 8` units
BC = `sqrt ((10 + 1)^2 + (3 - 4)^2) = sqrt ( 1 + 1) = sqrt 2` units
AC = `sqrt ((-2 + 1)^2 + (1 - 4)^2) = sqrt (1 + 9) = sqrt 10` units
AB2+ BC2 = 8 + 2 = 10
AC2 = 10
∵ AB2+ BC2 = AC2
∴ A , B and C are the verices of a right angled triangle.
APPEARS IN
संबंधित प्रश्न
Name the type of quadrilateral formed, if any, by the following point, and give reasons for your answer:
(−3, 5), (3, 1), (0, 3), (−1, −4)
If Q (0, 1) is equidistant from P (5, − 3) and R (x, 6), find the values of x. Also find the distance QR and PR.
`" Find the distance between the points" A ((-8)/5,2) and B (2/5,2)`
Find the distance between the following pair of point in the coordinate plane.
(1 , 3) and (3 , 9)
A point P lies on the x-axis and another point Q lies on the y-axis.
Write the ordinate of point P.
Calculate the distance between the points P (2, 2) and Q (5, 4) correct to three significant figures.
The coordinates of the point which is equidistant from the three vertices of the ΔAOB as shown in the figure is ______.
Point P(0, 2) is the point of intersection of y-axis and perpendicular bisector of line segment joining the points A(–1, 1) and B(3, 3).
What is the distance of the point (– 5, 4) from the origin?
The distance of the point (5, 0) from the origin is ______.
