Advertisements
Advertisements
प्रश्न
Ratio of areas of ∆MNO, ∆MOP and ∆MPQ in the given figure is ______.
विकल्प
2:1:3
1:3:2
2:3:1
1:2:3
उत्तर
Ratio of areas of ∆MNO, ∆MOP and ∆MPQ in the given figure is 2:1:3.
Explanation:
We know that, area of triangle = `1/2` × base × height
So, area of triangle MNO = `1/2` × NO × MO
= `1/2` × 5 × 4
= `1/2` × 20
= 10 cm2
Area of triangle MOP = `1/2` × MO × OP
= `1/2` × 5 × 2
= `1/2` × 10
= 5 cm2
Area of triangle MPQ = `1/2` × MO × PQ ......[MP = MO]
= `1/2` × 5 × 6
= `1/2` × 30
= 15 cm2
So, the ratio of area = 10:5:15 ......[Divide each by 5]
Then we get, 2:1:3
APPEARS IN
संबंधित प्रश्न
Prove that the area of a triangle with vertices (t, t −2), (t + 2, t + 2) and (t + 3, t) is independent of t.
For what value of k are the points (k, 2 – 2k), (–k + 1, 2k) and (–4 – k, 6 – 2k) are collinear ?
Find the area of a triangle with vertices at the point given in the following:
(1, 0), (6, 0), (4, 3)
Show that points A (a, b + c), B (b, c + a), C (c, a + b) are collinear.
Find the area of the following triangle:
Find the value of y for which the points A(-3, 9), B(2,y) and C(4,-5) are collinear.
If the points P(-3, 9), Q(a, b) and R(4, -5) are collinear and a+b=1, find the value of a and b.
Find the value(s) of k so that the quadratic equation x2 − 4kx + k = 0 has equal roots.
The table given below contains some measures of the right angled triangle. Find the unknown values.
Base | Height | Area |
? | 12 m | 24 sq.m |
Area of triangle MNO in the figure is ______.