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Show that (4pq + 3q)Square2 - (4pq - 3q)Square2 = 48pqsquare2 - Mathematics

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प्रश्न

Show that `(4pq + 3q)^2 - (4pq - 3q)^2 = 48pq^2`

उत्तर

L.H.S = (4pq + 3q)2 - (4pq - 3q)2

= (4pq)2 + 2(4pq)(3q) + (3q)2 = [(4pq)2 - 2(4pq)(3q) +(3q)2]

= 16p2q2 + 24pq2 + 9q2 - [16p2q2 - 24pq2 + 9q2]

= 16p2q2 + 24pq2 + 9q2 - 16p2q2 +24pq2 - 9q2

= 48pq2 = R.H.S

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Algebraic Expressions and Identities - Exercise 9.5 [पृष्ठ १५१]

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एनसीईआरटी Mathematics [English] Class 8
अध्याय 9 Algebraic Expressions and Identities
Exercise 9.5 | Q 5.4 | पृष्ठ १५१

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