Advertisements
Advertisements
प्रश्न
Show that the following points are collinear:
(i) A(2,-2), B(-3, 8) and C(-1, 4)
उत्तर
`"Let " A(x_1=2,y_1=-2) B (x_2=-3, y_2=8) and C(x_3=-1,y_3=4)` be the given points.
`No w , x_1 (y_1-y)3)+x_2(y_3-y_1) + x_3(y_1-y_2)`
=2(8-4)+(-3)(4+2)+(-1)(-2-8)
=8-18+10
=0
Hence, the given points are collinear.
APPEARS IN
संबंधित प्रश्न
Find the area of the following triangle:
In a ΔABC, AB = 15 cm, BC = 13 cm and AC = 14 cm. Find the area of ΔABC and hence its altitude on AC ?
Find the area of the blades of thc magnetic compass shown in Fig.. 12.27. (Take √11 = 3.32).
prove that the points A (7, 10), B(-2, 5) and C(3, -4) are the vertices of an isosceles right triangle.
For what value of k(k>0) is the area of the triangle with vertices (-2, 5), (k, -4) and (2k+1, 10) equal to 53 square units?
For what values of k are the points A(8, 1) B(3, -2k) and C(k, -5) collinear.
What is the area of a triangle with base 4.8 cm and height 3.6 cm?
If A, B, C are the angles of a triangle, then ∆ = `|(sin^2"A", cot"A", 1),(sin^2"B", cot"B", 1),(sin^2"C", cot"C", 1)|` = ______.
Triangles having the same base have equal area.
Ratio of the area of ∆WXY to the area of ∆WZY is 3:4 in the given figure. If the area of ∆WXZ is 56 cm2 and WY = 8 cm, find the lengths of XY and YZ.