Advertisements
Advertisements
प्रश्न
What is the area of a triangle with base 4.8 cm and height 3.6 cm?
उत्तर
We have the base of a triangle = 4.8 cm
Height of a triangle = 3.6 cm
∴ Area of a triangle = `1/2` × base × height
= `1/2xx4.8xx3.6`
= `(4.8xx3.6)/2`
= `17.28/2`
= 8.64 cm2
संबंधित प्रश्न
Find the relation between x and y if, the points A(x, y), B(-5, 7) and C(-4, 5) are collinear.
Prove that the points (2, – 2), (–3, 8) and (–1, 4) are collinear
Prove that the points (2a, 4a), (2a, 6a) and `(2a + sqrt3a, 5a)` are the vertices of an equilateral triangle.
If the coordinates of the mid-points of the sides of a triangle are (3, 4) (4, 6) and (5, 7), find its vertices.
Find the area of a triangle whose sides are 9 cm, 12 cm and 15 cm ?
Show that the points (-3, -3),(3,3) and C (-3 `sqrt(3) , 3 sqrt(3))` are the vertices of an equilateral triangle.
Prove that the points A (a,0), B( 0,b) and C (1,1) are collinear, if `( 1/a+1/b) =1`.
The table given below contains some measures of the right angled triangle. Find the unknown values.
Base | Height | Area |
? | 12 m | 24 sq.m |
If the points (3, -2), (x, 2), (8, 8) are collinear, then find the value of x.
Find the coordinates of the point Q on the x-axis which lies on the perpendicular bisector of the line segment joining the points A(–5, –2) and B(4, –2). Name the type of triangle formed by the points Q, A and B.