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Solve: 11(X - 5) + 10(Y - 2) + 54 = 0 7(2x - 1) + 9(3y - 1) = 25 - Mathematics

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प्रश्न

Solve :
11(x - 5) + 10(y - 2) + 54 = 0
7(2x - 1) + 9(3y - 1) = 25

योग

उत्तर

11( x - 5 ) + 10( y - 2 ) + 54 = 0             (given)
⇒ 11x - 55 + 10y - 20 + 54 = 0
⇒ 11x + 10y - 21 = 0
⇒ 11x + 10y = 21                                 ....(1)

7( 2x - 1 ) + 9(3y - 1) = 25                     (given)
⇒ 14x - 7 + 27y - 9 = 25
⇒ 14x + 27y - 16 = 25
⇒ 14x + 27y = 41                               .....(2)

Multiplying equation (1) by 27 and equation (2) by 10, we get,
297x + 270y = 567                            ....(3)
140x + 270y = 410                            .....(4)

Subtracting equation (4) from equation (3), we get
157x = 157
⇒ x = 1

Substituting x = 1 in equation (1), we get,
11 x 1 + 10y = 21
⇒  10y = 10
⇒  y = 1
∴ Solution set is x = 1 and y = 1.

shaalaa.com
Methods of Solving Simultaneous Linear Equations by Elimination Method - Method of Elimination by Equating Coefficients
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Simultaneous (Linear) Equations (Including Problems) - Exercise 6 (B) [पृष्ठ ८१]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 6 Simultaneous (Linear) Equations (Including Problems)
Exercise 6 (B) | Q 17 | पृष्ठ ८१
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