Advertisements
Advertisements
प्रश्न
Solve:
2x4 – 5x2 + 3 = 0
उत्तर
2x4 – 5x² + 3 = 0
`=>` 2x4 – 3x2 – 2x2 + 3 = 0
`=>` x2(2x2 – 3) – 1(2x2 – 3) = 0
`=>` (2x2 – 3)(x2 – 1) = 0
If 2x2 – 3 = 0 or x2 – 1 = 0
Then `x^2 = 3/2` or `x^2 = 1`
`=> x = +- sqrt(3/2)` or `x = +- 1`
APPEARS IN
संबंधित प्रश्न
Write the following quadratic equation in a standard form: 3x2 =10x + 7.
Without solving the following quadratic equation, find the value of m for which the given equation has equation has real and equal roots.
`x^2 + 2(m - 1)x + (m + 5) = 0`
Solve: x4 – 2x² – 3 = 0.
`2x^2+ax-a^2=0`
`x^2+5x-(a^2+a-6)=0`
`x/(x+1)+(x+1)/x=2 4/15, x≠ 0,1`
Solve:
`x/3 + 3/(6 - x) = (2(6 +x))/15; (x ≠ 6)`
If x = −3 and x = `2/3` are solutions of quadratic equation mx2 + 7x + n = 0, find the values of m and n.
Solve :
`3x^2 - 2sqrt6x + 2 = 0`
Solve the following equation by reducing it to quadratic equation:
`sqrt(3x^2 - 2) + 1 = 2x`.