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प्रश्न
Solve` 4sqrt3x^2+5x-2sqrt3=0`
उत्तर
`4sqrt3x^2+5x-2sqrt3=0`
⇒ `4sqrt3x^2+8x-3x-2sqrt3=0`
⇒`4x(sqrt3x+2)-sqrt3 (sqrt3x+2)=0`
⇒`(sqrt3x+2=0) or 4x-sqrt3=0`
⇒`sqrt3+2=0 or 4x-sqrt3=0`
⇒`x=-2/sqrt3=(-2sqrt3)/3 or x=sqrt3/4`
Hence, `(-2sqrt3)/3 and sqrt3/4` are the roots of the given equation.
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Solution:
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Then we can take another root as any number like a positive or negative number or zero. Here I am taking another root of the quadratic equation as 2.
Then we can form a word problem as below,
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