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प्रश्न
Study the double bar graph given below and answer the questions that follow:
- What information is compared in the above given double bar graph?
- Calculate the ratio of minimum temperatures in the year 2008 to the year 2009 for the month of November.
- For how many months was the minimum temperature in the year 2008 greater than that of year 2009? Name those months.
- Find the average minimum temperature for the year 2008 for the four months.
- In which month is the variation in the two temperatures maximum?
उत्तर
a. The above double bar graph compares the minimum temperature during the month November to February for the years 2008 and 2009.
b. Minimum temperature of November in the year 2008 = 18°C
Minimum temperature of November in the year 2009 = 15°C
∴ Required ratio = 18/15 = 18:15 = 6:5
c. We can clearly see from the double bar graph that the minimum temperature in the year 2008 greater than that of the year 2009 for the month of February and November.
d. Average minimum temperature for the year 2008
= `"Total temperature for the year 2008 in four months"/4`
= `(18 + 11 + 4 + 12)/4`
= `45/4`
= 11.25
e. Difference of the temperature for different months can be shown by the following table:
| Month | Difference of temperature |
| November | 18 – 15 = 3 |
| December | 12 – 11 = 1 |
| January | 5 – 4 = 1 |
| Febuary | 12 – 8 = 4 |
From the above table, it is clear that for the month of February variation in two temperatures is maximum.
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संबंधित प्रश्न
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| Temperatures of the cities as on 20.6.2006 | ||
| City | Max. | Min. |
| Ahmedabad | 38ºC | 29ºC |
| Amritsar | 37ºC | 26ºC |
| Banglore | 28ºC | 21ºC |
| Chennai | 36ºC | 27ºC |
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| Jammu | 41ºC | 26ºC |
| Mumbai | 32ºC | 27ºC |
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