हिंदी
तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा ११

Suppose unknowingly you wrote the universal gravitational constant value as G = 6.67 × 1011. instead of the correct value, G = 6.67 × 10−11, - Physics

Advertisements
Advertisements

प्रश्न

Suppose unknowingly you wrote the universal gravitational constant value as G = 6.67 × 1011. instead of the correct value, G = 6.67 × 10−11, what is the acceleration due to gravity g' for this incorrect G? According to this new acceleration due to gravity, what will be your weight W'?

संख्यात्मक

उत्तर

Data: Incorrect Gravitational constant G = 6.67 × 1011 Nm2 kg−2

Mass of the Earth Me = 5.972 × 1024 kg

Radius of the earth Re = 6371 km (or) 6371 × 103 m

Acceleration due to gravity g' = `"GM"_"e"/"R"_"e"^2`

g' = `(6.67 xx 10^11 xx 5.97 xx 10^24)/((6371 xx 10^3)^2)`

= `(39.8332 xx 10^35)/(4.0589641 xx 10^13)`

= 9.81 × 1022

g' = 1022 g

New weight W' = Mg' = M(1022 g) = 1022 mg

W' = 1022 W

shaalaa.com
Introduction to Gravitation
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Gravitation - Evaluation [पृष्ठ ४६]

APPEARS IN

सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 6 Gravitation
Evaluation | Q V. 9. | पृष्ठ ४६
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×