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The cost of 4 pencils, 3 pens and 2 books is ₹ 150. The cost of 1 pencil, 2 pens and 3 books is ₹ 125. The cost of 6 pencils, 2 pens and 3 books is ₹ 175. Find the cost of each item by using matrices. - Mathematics and Statistics

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प्रश्न

The cost of 4 pencils, 3 pens, and 2 books is ₹ 150. The cost of 1 pencil, 2 pens, and 3 books is ₹ 125. The cost of 6 pencils, 2 pens, and 3 books is ₹ 175. Find the cost of each item by using matrices.

योग

उत्तर

Let the cost of 1 pencil, 1 pen and 1 book be ₹ x, ₹ y, ₹ z respectively.

According to the given conditions,

4x + 3y + 2z = 150

x + 2y + 3z = 125

6x + 2y + 3z = 175

The equations can be written in matrix form as:

`[(4,3,2),(1,2,3),(6,2,3)] [("x"),("y"),("z")] = [(150),(125),(175)]`

By R1 ↔ R2, we get,

`[(1,2,3),(4,3,2),(6,2,3)] [("x"),("y"),("z")] = [(125),(150),(175)]`

By R2 - 4R1 and R3 - 6R1, we get,

`[(1,2,3),(0,-5,-10),(0,-10,-15)] [("x"),("y"),("z")] = [(125),(-350),(-575)]`

By R3 - 2R2, we get,

`[(1,2,3),(0,-5,-10),(0,0,5)] [("x"),("y"),("z")] = [(125),(-350),(125)]`

∴ `[("x" + 2"y" + 3"z"),(0 - "5y" - 10"z"),(0 + 0 + "5z")] = [(125),(-350),(125)]`

By equality of matrices,

x + 2y + 3z = 125    ...(1)

- 5y - 10z = - 350    ...(2)

5z = 125       ...(3)

From (3), z = 25

Substituting z = 25 in (2), we get

- 5y - 10(25) = - 350

∴ - 5y = - 350 + 250 = - 100

∴ y = 20

Substituting y = 20, z = 25 in (1), we get

x + 2(20) + 3(25) = 125

∴ x = 125 - 40 - 75 = 10

∴ x = 10, y = 20, y = 25

Hence, the cost of 1 pencil is ₹ 10, 1 pen is ₹ 20 and 1 book is ₹ 25.

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Notes

[Note: Answer to cost of a pen in the textbook is incorrect.]

Application of Matrices
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Matrics - Miscellaneous exercise 2 (B) [पृष्ठ ६३]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 12 Standard HSC Maharashtra State Board
अध्याय 2 Matrics
Miscellaneous exercise 2 (B) | Q 4 | पृष्ठ ६३

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