Advertisements
Advertisements
प्रश्न
The first and the last terms of an A.P. are 8 and 350 respectively. If its common difference is 9, how many terms are there and what is their sum?
उत्तर
First term, a = 8
Common difference, d = 9
Let the nth term be the last term.
∴ l = an = 350
⇒ a + (n − 1) d = 350
⇒ 8 + (n − 1) × 9 = 350
⇒ (n − 1) × 9 = 342
`rArr n-1=342/9=38`
`rArrn=38+1=39`
Thus, there are 39 terms in the given A.P.
Sum of 39 trems , `S_39=39/2(a+a_39)`
`=39/2xx(8+350)`
`=39/2xx358`
`=6981`
APPEARS IN
संबंधित प्रश्न
How many terms of the A.P. 27, 24, 21, .... should be taken so that their sum is zero?
Find the sum given below:
34 + 32 + 30 + ... + 10
The sum of three terms of an A.P. is 21 and the product of the first and the third terms exceed the second term by 6, find three terms.
Find the sum of the first 22 terms of the A.P. : 8, 3, –2, ………
Which term of the sequence 114, 109, 104, ... is the first negative term?
If 18, a, b, −3 are in A.P., the a + b =
How many terms of the A.P. 27, 24, 21, …, should be taken so that their sum is zero?
How many terms of the A.P. 25, 22, 19, … are needed to give the sum 116 ? Also find the last term.
Find the sum of first 1000 positive integers.
Activity :- Let 1 + 2 + 3 + ........ + 1000
Using formula for the sum of first n terms of an A.P.,
Sn = `square`
S1000 = `square/2 (1 + 1000)`
= 500 × 1001
= `square`
Therefore, Sum of the first 1000 positive integer is `square`
If the first term of an AP is –5 and the common difference is 2, then the sum of the first 6 terms is ______.