Advertisements
Advertisements
प्रश्न
The following table shows the cumulative frequency distribution of marks of 800 students in an examination:
| Marks | Number of students |
| Below 10 | 10 |
| Below 20 | 50 |
| Below 30 | 130 |
| Below 40 | 270 |
| Below 50 | 440 |
| Below 60 | 570 |
| Below 70 | 670 |
| Below 80 | 740 |
| Below 90 | 780 |
| Below 100 | 800 |
Construct a frequency distribution table for the data above.
उत्तर
| Marks | Number of students | C.I. | No. of students |
| Below 10 | 10 | 0 – 10 | 10 |
| Below 20 | 50 | 10 – 20 | 50 – 10 = 40 |
| Below 30 | 130 | 20 – 30 | 130 – 50 = 80 |
| Below 40 | 270 | 30 – 40 | 270 – 130 = 140 |
| Below 50 | 440 | 40 – 50 | 440 – 270 = 170 |
| Below 60 | 570 | 50 – 60 | 570 – 440 = 130 |
| Below 70 | 670 | 60 – 70 | 670 – 570 = 100 |
| Below 80 | 740 | 70 – 80 | 740 – 670 = 70 |
| Below 90 | 780 | 80 – 90 | 780 – 740 = 40 |
| Below 100 | 800 | 90 – 100 |
800 – 780 = 20 |
APPEARS IN
संबंधित प्रश्न
The following table gives production yield per hectare of wheat of 100 farms of a village.
| Production yield (in kg/ha) | 50 − 55 | 55 − 60 | 60 − 65 | 65 − 70 | 70 − 75 | 75 − 80 |
| Number of farms | 2 | 8 | 12 | 24 | 38 | 16 |
Change the distribution to a more than type distribution and draw ogive.
The following table gives the production yield per hectare of wheat of 100 farms of a village.
| Production Yield (kg/ha) | 50 –55 | 55 –60 | 60 –65 | 65- 70 | 70 – 75 | 75 80 |
| Number of farms | 2 | 8 | 12 | 24 | 238 | 16 |
Change the distribution to a ‘more than type’ distribution and draw its ogive. Using ogive, find the median of the given data.
For a frequency distribution, mean, median and mode are connected by the relation
In the formula `barx=a+h((sumf_iu_i)/(sumf_i))`, for finding the mean of grouped frequency distribution ui = ______.
Consider the following distribution:
| Marks obtained | Number of students |
| More than or equal to 0 | 63 |
| More than or equal to 10 | 58 |
| More than or equal to 20 | 55 |
| More than or equal to 30 | 51 |
| More than or equal to 40 | 48 |
| More than or equal to 50 | 42 |
The frequency of the class 30 – 40 is:
Look at the following table below.
| Class interval | Classmark |
| 0 - 5 | A |
| 5 - 10 | B |
| 10 - 15 | 12.5 |
| 15 - 20 | 17.5 |
The value of A and B respectively are?
Form the frequency distribution table from the following data:
| Marks (out of 90) | Number of candidates |
| More than or equal to 80 | 4 |
| More than or equal to 70 | 6 |
| More than or equal to 60 | 11 |
| More than or equal to 50 | 17 |
| More than or equal to 40 | 23 |
| More than or equal to 30 | 27 |
| More than or equal to 20 | 30 |
| More than or equal to 10 | 32 |
| More than or equal to 0 | 34 |
Find the unknown entries a, b, c, d, e, f in the following distribution of heights of students in a class:
| Height (in cm) |
Frequency | Cumulative frequency |
| 150 – 155 | 12 | a |
| 155 – 160 | b | 25 |
| 160 – 165 | 10 | c |
| 165 – 170 | d | 43 |
| 170 – 175 | e | 48 |
| 175 – 180 | 2 | f |
| Total | 50 |
The following are the ages of 300 patients getting medical treatment in a hospital on a particular day:
| Age (in years) | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 | 60 – 70 |
| Number of patients | 60 | 42 | 55 | 70 | 53 | 20 |
Form: Less than type cumulative frequency distribution.
Given below is a cumulative frequency distribution showing the marks secured by 50 students of a class:
| Marks | Below 20 | Below 40 | Below 60 | Below 80 | Below 100 |
| Number of students | 17 | 22 | 29 | 37 | 50 |
Form the frequency distribution table for the data.
