हिंदी

Consider the following distribution: Marks obtained Number of students More than or equal to 0 63 More than or equal to 10 58 More than or equal to 20 55 More than or equal to 30 51 - Mathematics

Advertisements
Advertisements

प्रश्न

Consider the following distribution:

Marks obtained Number of students
More than or equal to 0 63
More than or equal to 10 58
More than or equal to 20 55
More than or equal to 30 51
More than or equal to 40 48
More than or equal to 50 42

The frequency of the class 30 – 40 is:

विकल्प

  • 3

  • 4

  • 48

  • 51

MCQ

उत्तर

3

Explanation:

Marks obtained Number of students
0 – 10 (63 – 58) = 5
10 – 20 (58 – 55) = 3
20 – 30 (55 – 51) = 4
30 – 40 (51 – 48) = 3
40 – 50 (48 – 42) = 6
50... 42 = 42

Hence, frequency of the class interval 30 – 40 is 3.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Statistics and Probability - Exercise 13.1 [पृष्ठ १५९]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
अध्याय 13 Statistics and Probability
Exercise 13.1 | Q 11 | पृष्ठ १५९

संबंधित प्रश्न

The following frequency distribution gives the monthly consumption of electricity of 64 consumers of locality.

Monthly consumption (in units) 65 – 85 85 – 105 105 – 125 125 – 145 145 – 165 165 – 185
Number of consumers 4 5 13 20 14 8

Form a ‘ more than type’ cumulative frequency distribution.


The median of a given frequency distribution is found graphically with the help of


The mean of a discrete frequency distribution xi / fi, i = 1, 2, ......, n is given by


In the formula  `barx=a+h((sumf_iu_i)/(sumf_i))`, for finding the mean of grouped frequency distribution ui = ______.


Consider the following frequency distribution :

Class: 0-5      6-11   12-17  18-23   24-29
Frequency:   13 10 15 8 11

The upper limit of the median class is 


If the median of the following frequency distribution is 32.5. Find the values of f1 and f2.

Class 0-10 10-20 20-30 30-40 40-50 50-60 60-70 Total
Frequency f1 5 9 12 f2 3 2 40

For one term, absentee record of students is given below. If mean is 15.5, then the missing frequencies x and y are.

Number of days 0 - 5 5 - 10 10 - 15 15 - 20 20 - 25 25 - 30 30 - 35 35 - 40 TOTAL
Total Number of students 15 16 x 8 y 8 6 4 70

The following table shows the cumulative frequency distribution of marks of 800 students in an examination:

Marks Number of students
Below 10 10
Below 20 50
Below 30 130
Below 40 270
Below 50 440
Below 60 570
Below 70 670
Below 80 740
Below 90 780
Below 100 800

Construct a frequency distribution table for the data above.


Find the unknown entries a, b, c, d, e, f in the following distribution of heights of students in a class:

Height
(in cm)
Frequency Cumulative frequency
150 – 155 12 a
155 – 160 b 25
160 – 165 10 c
165 – 170 d 43
170 – 175 e 48
175 – 180 2 f
Total 50  

Given below is a cumulative frequency distribution showing the marks secured by 50 students of a class:

Marks Below 20 Below 40 Below 60 Below 80 Below 100
Number of students 17 22 29 37 50

Form the frequency distribution table for the data.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×