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प्रश्न
The following frequency distribution gives the monthly consumption of electricity of 64 consumers of locality.
| Monthly consumption (in units) | 65 – 85 | 85 – 105 | 105 – 125 | 125 – 145 | 145 – 165 | 165 – 185 |
| Number of consumers | 4 | 5 | 13 | 20 | 14 | 8 |
Form a ‘ more than type’ cumulative frequency distribution.
उत्तर
The cumulative frequency distribution table of more than type is as follows:
| Monthly consumption (in units) (lower class limits) | Cumulative frequency (𝑐𝑓) |
| More than 65 | 60 + 4 =64 |
| More than 85 | 55 + 5 = 60 |
| More than 105 | 42 + 13 = 55 |
| More than 125 | 22 + 20 = 42 |
| More than 145 | 8 + 14 = 22 |
| More than 165 | 8 |
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संबंधित प्रश्न
During the medical check-up of 35 students of a class, their weights were recorded as follows:
| Weight (in kg | Number of students |
| Less than 38 | 0 |
| Less than 40 | 3 |
| Less than 42 | 5 |
| Less than 44 | 9 |
| Less than 46 | 14 |
| Less than 48 | 28 |
| Less than 50 | 32 |
| Less than 52 | 35 |
Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.
The monthly consumption of electricity (in units) of some families of a locality is given in the following frequency distribution:
| Monthly Consumption (in units) | 140 – 160 | 160 – 180 | 180 – 200 | 200 – 220 | 220 – 240 | 240 – 260 | 260 - 280 |
| Number of Families | 3 | 8 | 15 | 40 | 50 | 30 | 10 |
Prepare a ‘more than type’ ogive for the given frequency distribution.
The table given below shows the weekly expenditures on food of some households in a locality
| Weekly expenditure (in Rs) | Number of house holds |
| 100 – 200 | 5 |
| 200- 300 | 6 |
| 300 – 400 | 11 |
| 400 – 500 | 13 |
| 500 – 600 | 5 |
| 600 – 700 | 4 |
| 700 – 800 | 3 |
| 800 – 900 | 2 |
Draw a ‘less than type ogive’ and a ‘more than type ogive’ for this distribution.
From the following frequency, prepare the ‘more than’ ogive.
| Score | Number of candidates |
| 400 – 450 | 20 |
| 450 – 500 | 35 |
| 500 – 550 | 40 |
| 550 – 600 | 32 |
| 600 – 650 | 24 |
| 650 – 700 | 27 |
| 700 – 750 | 18 |
| 750 – 800 | 34 |
| Total | 230 |
Also, find the median.
Calculate the missing frequency form the following distribution, it being given that the median of the distribution is 24
| Age (in years) | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 |
| Number of persons |
5 | 25 | ? | 18 | 7 |
The mode of a frequency distribution can be determined graphically from ______.
Consider the following frequency distributions
| Class | 65 - 85 | 85 - 105 | 105 - 125 | 125 - 145 | 145 - 165 | 165 - 185 | 185-205 |
| Frequency | 4 | 5 | 13 | 20 | 14 | 7 | 4 |
The difference of the upper limit of the median class and the lower limit of the modal class is?
The marks obtained by 100 students of a class in an examination are given below.
| Mark | No. of Student |
| 0 - 5 | 2 |
| 5 - 10 | 5 |
| 10 - 15 | 6 |
| 15 - 20 | 8 |
| 20 - 25 | 10 |
| 25 - 30 | 25 |
| 30 - 35 | 20 |
| 35 - 40 | 18 |
| 40 - 45 | 4 |
| 45 - 50 | 2 |
Draw 'a less than' type cumulative frequency curves (ogive). Hence find the median.
Calculate the mean of the following frequency distribution :
| Class: | 10-30 | 30-50 | 50-70 | 70-90 | 90-110 | 110-130 |
| Frequency: | 5 | 8 | 12 | 20 | 3 | 2 |
If the sum of all the frequencies is 24, then the value of z is:
| Variable (x) | 1 | 2 | 3 | 4 | 5 |
| Frequency | z | 5 | 6 | 1 | 2 |
