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प्रश्न
“The inequality `2^sintheta + 2^costheta ≥ 2^(1/sqrt(2))` holds for all real values of θ”
विकल्प
True
False
उत्तर
This statement is True.
Explanation:
Since `2sin^theta` and `2^costheta` are positive real numbers, so A.M. (Arithmetic Mean) of these two numbers is greater or equal to their G.M. (Geometric Mean)
Hence `(2^sintheta + 2^costheta)/2 ≥ sqrt(2^sintheta xx 2^costheta)`
= `sqrt(2^(sintheta + costheta))`
`≥ 2 ^((sintheta + costheta)/2) = 2^(1/sqrt(2)(1/sqrt(2) sintheta + 1/sqrt(2) cos theta))`
`≥ 2^(1/sqrt(2) sin(pi/4 + theta))`
Since, `-1 ≤ sin(pi/4 + theta) ≤ 1`
We have `(2^sintheta + 2^costheta)/2 ≥ 2^((-1)/sqrt(2))`
⇒ `2^sintheta + 2^costheta ≥ 2^(1 - 1/sqrt(2))`
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