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प्रश्न
The metal of Group 2 from top to bottom arc Be, Mg, Ca, Sr, and Ba.
1) Which one of these elements will form ions most readily and why?
2) State the common feature in the electronic configuration of all these elements.
उत्तर
1) In group 2, the atomic size increases down the group. As the atomic size increases, the nuclear charge decreases. Due to this, electrons of the outermost shell lie further away from the nucleus making the removal of electrons easy. So, Ba will form ions readily.
2) All the elements have 2 electrons in their valence shell.
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संबंधित प्रश्न
Differentiate between Normal elements and Transition elements.
Fill in the blank in the following statement:
In going across a period (right to left) in periodic table, the atomic size of the atom ...............
Study the extract of the Periodic Table given below and answer the questions that follow. Give the alphabet corresponding to the element in question. DO NOT repeat an element.
Which is an inert gas?
State the number of elements in period 1, period 2 and period 3 of the periodic table.
The following questions refer to the Periodic Table.
Name the first and last element in period 2.
The elements of one short period of the periodic table are given below in order from left to right:
Li | Be | B | C | O | F | Ne |
Place the three elements fluorine, beryllium and nitrogen in the order of increasing electronegativity.
An element belongs to the third period and Group IIIA (13) of the periodic table. State: the name of the element.
An element A has 2 electrons in its fourth shell. State:
is it an oxidising or reducing agent
Based on the group valency of element write the molecular formula of the following compound giving justification:
Oxide of first group elements.
Name the elements in the correct order of their increasing atomic numbers present in the first, second, and third short periods of the periodic table.
State which of the elements are –
- metallic
- non-metallic
- noble gases
in each of the periods 2 and 3.