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प्रश्न
The perimeter of the triangle formed by the points (0, 0), (0, 1) and (0, 1) is
विकल्प
1 ± \[\sqrt{2}\]
- \[\sqrt{2}\] + 1
3
- \[2 + \sqrt{2}\]
उत्तर
We have a triangle ΔABC whose co-ordinates are A (0, 0); B (1, 0); C (0, 1). So clearly the triangle is right angled triangle, right angled at A. So,
AB = 1 unit
AC = 1 unit
Now apply Pythagoras theorem to get the hypotenuse,
`BC = sqrt(AB^2 + Ac^2 )`
`= sqrt(2)`
So the perimeter of the triangle is,
= AB + BC + AC
`= 1 + 1+ sqrt(2)`
`= 2 + sqrt(2)`
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