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प्रश्न
The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. Find the curved surface area of the bucket.
उत्तर
Let R and r be the radii of the top base of the bucket, respectively, and let/ be its slant height.
Then, curved surface area of the bucket
= curved surface area of the frustum of the cone
= π l(R+r)
`=22/7xx45xx35(28+7)"cm"^2`
`=(22/7xx45xx35)"cm"^2`
= 4950 cm2
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