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प्रश्न
The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122m, 22m, and 120m (see the given figure). The advertisements yield an earning of ₹ 5000 per m2 per year. A company hired one of its walls for 3 months. How much rent did it pay?
उत्तर
The sides of the triangle (i.e., a, b, c) are 122 m, 22 m, and 120 m, respectively.
Perimeter of triangle = (122 + 22 + 120) m
2s = 264 m
s = 132 m
By Heron’s formula,
Area of triangle = `sqrt(s(s-a)(s-b)(s-c))`
Area of given triangle = `[sqrt(132(132-122)(132-22)(132-120))]m^2`
= `[sqrt(132(10)(110)(12))]m^2 = 1320m^2`
Rent of 1 m2 area per year = ₹ 5000
Rent of 1 m2 area per month = `₹ 5000/12`
Rent of 1320 m2 area for 3 months
= `₹ (5000/12xx3xx1320)`
= ₹ (5000 × 330)
= ₹ 16,50,000
Therefore, the company had to pay ₹ 16,50,000.
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