Advertisements
Advertisements
प्रश्न
Two roots of quadratic equation is given ; frame the equation.
10 and –10
उत्तर
10 and –10
Sum of roots = 10 + (–10) = 0
Product of roots = \[10 \times \left( - 10 \right) = - 100\]
The general form of the quadratic equation is \[x^2 - \left( \text{ Sum of roots } \right)x + \text{ product of roots } = 0\]
So, the quadratic equation will be
\[x^2 - 0x - 100 = 0\]
\[ \Rightarrow x^2 - 100 = 0\]
APPEARS IN
संबंधित प्रश्न
Solve using formula.
x2 + 6x + 5 = 0
Solve using formula.
3m2 + 2m – 7 = 0
Solve using formula.
5m2 – 4m – 2 = 0
Solve using formula.
y2 + `1/3`y = 2.
The roots of the following quadratic equation is real and equal, find k.
3y2 + ky +12 = 0
Find the value of discriminant of the following equation.
2y2 − y + 2 = 0
Two roots of quadratic equation is given ; frame the equation.
\[1 - 3\sqrt{5} \text{ and } 1 + 3\sqrt{5}\]
Determine the nature of root of the quadratic equation.
\[3 x^2 - 5x + 7 = 0\]
Determine the nature of root of the quadratic equation.
\[\sqrt{3} x^2 + \sqrt{2}x - 2\sqrt{3} = 0\]
Determine the nature of root of the quadratic equation.
m2 - 2m + 1 = 0
Find m if (m – 12) x2 + 2(m – 12) x + 2 = 0 has real and equal roots.
The difference between squares of two numbers is 120. The square of smaller number is twice the greater number. Find the numbers.
If α and β are the roots of the equation is 3x2 + x – 10 = 0, then the value of `1/α + 1/β` is ______.
If 2 and 5 are the roots of the quadratic equation, then complete the following activity to form quadratic equation:
Activity:
Let α = 2 and β = 5 are the roots of the quadratic equation.
Then quadratic equation is:
x2 − (α + β)x + αβ = 0
∴ `x^2 - (2 + square)x + square xx 5 = 0`
∴ `x^2 - square x + square = 0`