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Determine the Nature of Roots for Each of the Quadratic Equation. 3 X 2 − 5 X + 7 = 0 - Algebra

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प्रश्न

Determine the nature of root of the quadratic equation.

\[3 x^2 - 5x + 7 = 0\]

योग

उत्तर

\[3 x^2 - 5x + 7 = 0\] 

In order to find the nature of the roots we need to find the discriminant. 

\[D = b^2 - 4ac\]
\[a = 3, b = - 5, c = 7\]
\[D = \left( - 5 \right)^2 - 4 \times 3 \times 7 = 25 - 84 = - 59\]

Since, the D < 0 so, there is no real root. 

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अध्याय 2: Quadratic Equations - Problem Set 2 [पृष्ठ ५४]

APPEARS IN

बालभारती Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board
अध्याय 2 Quadratic Equations
Problem Set 2 | Q 6.1 | पृष्ठ ५४

संबंधित प्रश्न

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x2 – 7x + 5 = 0


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y2 = 7y


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x2 + 6x + 5 = 0


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x2 – 3x – 2 = 0


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5m2 – 4m – 2 = 0


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y2 + `1/3`y = 2.


Solve using formula.

5x2 + 13x + 8 = 0


The roots of the following quadratic equation is real and equal, find k.

3y+ ky +12 = 0


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 kx (x – 2) + 6 = 0


Find the value of discriminant of the following equation.

\[\sqrt{5} x^2 - x - \sqrt{5} = 0\]


One of the roots of quadratic equation \[2 x^2 + kx - 2 = 0\] is –2. find k.


Two roots of quadratic equation is given ; frame the equation.

 10 and –10


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\[1 - 3\sqrt{5} \text{ and } 1 + 3\sqrt{5}\] 


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Find quadratic equation such that its roots are square of sum of the roots and square of difference of the roots of equation \[2 x^2 + 2\left( p + q \right)x + p^2 + q^2 = 0\]


If 2 and 5 are the roots of the quadratic equation, then complete the following activity to form quadratic equation:

Activity:

Let α = 2 and β = 5 are the roots of the quadratic equation.

Then quadratic equation is:

x2 − (α + β)x + αβ = 0

∴ `x^2 - (2 + square)x + square xx 5 = 0`

∴ `x^2 - square x + square = 0`


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