Advertisements
Advertisements
प्रश्न
Using the information given of the following figure, find the values of a and b.
उत्तर
In ΔAEB and ΔCAD,
∠EAD = ∠CAD .........[Given]
∠ADC = ∠AEB .......[∵ ∠ADE = ∠AED { AE = AD }180° − ∠ADE = 180° − ∠AED = ∠ADC = ∠AEB]
AE = AD .........[Given]
∴ ΔAEB ≅ ΔCAD ....[ASA]
AC = AB .......[By C.P.C.T.]
2a + 2 = 7b − 1
⇒ 2a − 7b = − 3 ....(i)
CD = EB
⇒ a = 3b ....(ii)
Solving (i) and (ii), We get,
a = 9, b = 3
APPEARS IN
संबंधित प्रश्न
An isosceles triangle ABC has AC = BC. CD bisects AB at D and ∠CAB = 55°.
Find:
- ∠DCB
- ∠CBD
In the figure, given below, AB = AC.
Prove that: ∠BOC = ∠ACD.
Calculate x :
Prove that a triangle ABC is isosceles, if: altitude AD bisects angles BAC.
Prove that a triangle ABC is isosceles, if: bisector of angle BAC is perpendicular to base BC.
In the given figure, AD = AB = AC, BD is parallel to CA and angle ACB = 65°. Find angle DAC.
In triangle ABC; AB = AC and ∠A : ∠B = 8 : 5; find angle A.
ABC is a triangle. The bisector of the angle BCA meets AB in X. A point Y lies on CX such that AX = AY.
Prove that: ∠CAY = ∠ABC.
Use the given figure to prove that, AB = AC.
Prove that the medians corresponding to equal sides of an isosceles triangle are equal.