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प्रश्न
What is the locus of points which are equidistant from the given non-collinear point A, B and C? Justify your answer.
उत्तर
Let A, B, C be three distinct points on a line1. Any point equidistant from A and B lies on the perpendicular bisector of Ab. So, points equidistant from A and B lies on line m.
Similarly, points equidistant from B and C lies on line n which is the perpendicular bisector of BC.
Thus, any point equidistant from A, B and C must be common to both the lines m and n.
But m ⊥ AB and n ⊥ BC.
∴ m ⊥ AC and n ⊥ AC
⇒ m || n
So, no points is common to both m and n.
Hence, the required locus is the null set Φ.
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