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प्रश्न
उत्तर
We have to prove that ABCD is a rhombus
Slope of AC = `("y"_2 - "y"_1)/("x"_2 - "x"_1) = (5 - 8)/(0 - 5) = (-3)/(-5) = 3/5`
Slope of BD = `("y"_2 - "y"_1)/("x"_2 - "x"_1) = (9- 4)/(1 - 4) = 5/(-3)`
Thus,Slope of AC x slope of BD = -1
So, the diagnols AC and BC are perpendicular to each other.
Hence,ABCD is a rhombus.
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संबंधित प्रश्न
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