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A Bar Magnet is Released from Rest Along the Axis of a Very Long, Vertical Copper Tube. After Some Time the Magnet - Physics

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प्रश्न

A bar magnet is released from rest along the axis of a very long, vertical copper tube. After some time the magnet ____________ .

पर्याय

  • will stop in the tube

  • will move with almost contant speed

  • will move with an acceleration g

  • will oscillate

MCQ
रिकाम्या जागा भरा

उत्तर

will move with almost contant speed


As the magnet is moving under gravity, the flux linked with the copper tube will change because of the motion of the magnet. This will produce eddy currents in the body of the copper tube. According to Lenz's law, these induced currents oppose the fall of the magnet. So, the magnet will experience a retarding force. This force will continuously increase with increasing velocity of the magnet till it becomes equal to the force of gravity. After this, the net force on the magnet will become zero. Hence, the magnet will attain a constant speed.

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पाठ 16: Electromagnetic Induction - MCQ [पृष्ठ ३०४]

APPEARS IN

एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 16 Electromagnetic Induction
MCQ | Q 5 | पृष्ठ ३०४

संबंधित प्रश्‍न

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A bar magnet is moved in the direction indicated by the arrow between two coils PQ and CD. Predict the directions of induced current in each coil.


Consider the situation shown in figure. If the switch is closed and after some time it is opened again, the closed loop will show ____________ .


Two circular loops of equal radii are placed coaxially at some separation. The first is cut and a battery is inserted in between to drive a current in it. The current changes slightly because of the variation in resistance with temperature. During this period, the two loops _______________ .


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(a) The south pole faces the ring and the magnet moves towards it.
(b) The north pole faces the ring and the magnet moves towards it.
(c) The south pole faces the ring and the magnet moves away from it.
(d) The north pole faces the ring and the magnet moves away from it.


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  1. Write down equation for the acceleration of the wire XY.
  2. If B is independent of time, obtain v(t) , assuming v(0) = u0.
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Predict the direction of induced current in the situation described by the following figure.


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Use Lenz’s law to determine the direction of induced current in the situation described by the figure.

A circular loop being deformed into a narrow straight wire.


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