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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता १०

A bird is flying from A towards B at an angle of 35°, a point 30 km away from A. At B it changes its course of flight and heads towards C on a bearing of 48° and distance 32 km away. How far is C to - Mathematics

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प्रश्न

A bird is flying from A towards B at an angle of 35°, a point 30 km away from A. At B it changes its course of flight and heads towards C on a bearing of 48° and distance 32 km away. How far is C to the North of B?

(sin 55° = 0.8192, cos 55° = 0.5736, sin 42° = 0.6691, cos 42° = 0.7431)

बेरीज

उत्तर


Distance from C to the North of B is CD

In the right ∆BCD,

sin 42° = `"CD"/"BC"`

0.6691 = `"BD"/32`

∴ CD = 0.6691 × 32

= 21.41 km

Distance of C to the North B is 21.41 km

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पाठ 6: Trigonometry - Unit Exercise – 6 [पृष्ठ २६७]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
पाठ 6 Trigonometry
Unit Exercise – 6 | Q 7. (iii) | पृष्ठ २६७

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