Advertisements
Advertisements
प्रश्न
A ground is in the form of isosceles trapezium with parallel sides measuring 42 m and 36 m long. The distance between the parallel sides is 30 m. Find the cost of levelling it at the rate of ₹ 135 per sq.m
उत्तर
Parallel sides of the trapezium a = 42 m, b = 36 m
Also height h = 30 m
Area of the trapezium = `1/2` × h × (a + b) sq.unit
= `1/2` × 30 × (42 + 36) m2
= `1/2` × 30 × 78 m2
Area = 1,170 m2
Cost of levelling 1 m2 = ₹ 135
∴ Cost of levelling 1170 m2
= ₹ 1170 × ₹ 135
= ₹ 1,57,950
Cost of levelling the ground = ₹ 1,57,950
APPEARS IN
संबंधित प्रश्न
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 12 dm and 20 dm, altitude = 10 dm
Find the area of trapezium with base 15 cm and height 8 cm, if the side parallel to the given base is 9 cm long.
Top surface of a table is trapezium in shape. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.
The area of a trapezium is 384 cm2. Its parallel sides are in the ratio 3 : 5 and the perpendicular distance between them is 12 cm. Find the length of each one of the parallel sides.
If the area of a trapezium is 28 cm2 and one of its parallel sides is 6 cm, find the other parallel side if its altitude is 4 cm.
Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.
The area of the trapezium, if the parallel sides are measuring 8 cm and 10 cm and the height 5 cm is
The perimeter of a trapezium is 52 cm and its each non-parallel side is equal to 10 cm with its height 8 cm. Its area is ______.
The area of a trapezium become 4 times if its height gets doubled.
Find the area of the shaded portion in the following figure.