मराठी
तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता १०

A pole has to be erected at a point on the boundary of a circular ground of diameter 20 m in such a way that the difference of its distances from two diametrically opposite fixed gates P and Q on the - Mathematics

Advertisements
Advertisements

प्रश्न

A pole has to be erected at a point on the boundary of a circular ground of diameter 20 m in such a way that the difference of its distances from two diametrically opposite fixed gates P and Q on the boundary is 4 m. Is it possible to do so? If answer is yes at what distance from the two gates should the pole be erected?

बेरीज

उत्तर

Let “R” be the required location of the pole

Let the distance from the gate P is “x” m : PR = “x” m

The distance from the gate Q is (x + 4)m

∴ QR = (x + 4)m

In the right ∆PQR,

PR2 + QR2 = PQ2 (By Pythagoras theorem)

x2 + (x + 4)2 = 202

x2 + x2 + 16 + 8x = 400

2x2 + 8x – 384 = 0


x2 + 4x – 192 = 0  ...(divided by 2)

(x + 16) (x – 12) = 0

x + 16 = 0 or x – 12 = 0 ...[negative value is not considered]

x = – 16 or x = 12

Yes it is possible to erect

The distance from the two gates are 12 m and 16 m

shaalaa.com
Quadratic Equations
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Algebra - Exercise 3.12 [पृष्ठ ११६]

APPEARS IN

सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
पाठ 3 Algebra
Exercise 3.12 | Q 5 | पृष्ठ ११६
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×