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प्रश्न
A project schedule has the following characteristics
| Activity | 1 - 2 | 1 - 3 | 2 - 4 | 3 - 4 | 3 - 5 | 4 - 9 | 5 - 6 | 5 - 7 | 6 - 8 | 7 - 8 | 8 - 10 | 9 - 10 |
| Time | 4 | 1 | 1 | 1 | 6 | 5 | 4 | 8 | 1 | 2 | 5 | 7 |
Construct the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
उत्तर
E1 = 0
E2 = 0 + 4 = 4
E3 = 0 + 1 = 1
E4 = 4 + 1 = 5
E5 = 1 + 6 = 7
E6 = 7 + 4 = 11
E7 = 8 + 7 = 15
E8 = 15 + 2 = 7
E9 = 5 + 5 = 10
E10 = 17 + 5 = 22
L7 = 31
L10 = 22
L9 = 22 – 7 = 15
L8 = 22 – 5 = 17
L7 = 17 – 2 = 15
L6 = 17 – 1 = 16
L5 = (16 – 4) or (15 – 8)
whichever is minimum = 7
L4 = 15 – 5 = 10
L3 = (10 – 1) or (7 – 6)
whichever is minimum = 1
L2 = 10 – 1 = 9
L1 = 0
| Activity | Duration tij |
EST | EFT = EST + tij | LST = LFT – tij | LFT |
| 1 - 2 | 4 | 0 | 4 | 9 – 4 = 5 | 9 |
| 1 - 3 | 1 | 0 | 1 | 1 – 1 = 0 | 1 |
| 2 - 4 | 1 | 4 | 5 | 10 – 1 = 9 | 10 |
| 3 - 4 | 1 | 1 | 2 | 10 – 1 = 9 | 10 |
| 3 - 5 | 6 | 1 | 7 | 7 – 6 =1 | 7 |
| 4 - 9 | 5 | 5 | 10 | 15 – 5 =10 | 15 |
| 5 - 6 | 4 | 7 | 11 | 16 4 = 12 | 16 |
| 5 - 7 | 8 | 7 | 15 | 15 – 8 = 7 | 15 |
| 6 - 8 | 1 | 11 | 12 | 17 – 1 = 16 | 17 |
| 7 - 8 | 2 | 15 | 17 | 17 – 2 = 15 | 17 |
| 8 - 10 | 5 | 17 | 22 | 22 – 5 = 17 | 22 |
| 9 - 10 | 7 | 10 | 17 | 22 – 7 = 15 | 22 |
Since EFT and LFT is same on 1 - 3, 3 - 5, 5 - 7 and 7 - 8 and 8 - 10 the critical path is 1 - 3 - 5 - 7 - 8 - 10 and the duration is 22 time units.
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संबंधित प्रश्न
Draw the network for the project whose activities with their relationships are given below:
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Construct the network for each the projects consisting of various activities and their precedence relationships are as given below:
| Activity | A | B | C | D | E | F | G | H | I | J | K |
| Immediate Predecessors | - | - | - | A | B | B | C | D | E | H, I | F, G |
Draw the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
| Jobs | 1 - 2 | 1 - 3 | 2 - 4 | 3 - 4 | 3 - 5 | 4 - 5 | 4 - 6 | 5 - 6 |
| Duration | 6 | 5 | 10 | 3 | 4 | 6 | 2 | 9 |
The following table gives the activities of a project and their duration in days
| Activity | 1 - 2 | 1 - 3 | 2 - 3 | 2 - 4 | 3 - 4 | 3 - 5 | 4 - 5 |
| Duration | 5 | 8 | 6 | 7 | 5 | 4 | 8 |
Construct the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
The following table use the activities in a construction projects and relevant information
| Activity | 1 - 2 | 1 - 3 | 2 - 3 | 2 - 4 | 3 - 4 | 4 - 5 |
| Duration (in days) |
22 | 27 | 12 | 14 | 6 | 12 |
Draw the network for the project, calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and find the critical path. Compute the project duration.
In constructing the network which one of the following statements is false?
In the context of network, which of the following is not correct
Network problems have the advantage in terms of project
In critical path analysis, the word CPM mean
A Project has the following time schedule
| Activity | 1 - 2 | 2 - 3 | 2 - 4 | 3 - 5 | 4 - 6 | 5 - 6 |
| Duration (in days) |
6 | 8 | 4 | 9 | 2 | 7 |
Draw the network for the project, calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and find the critical path. Compute the project duration.
