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प्रश्न
A proton and an electron travelling along parallel paths enter a region of uniform magnetic field, acting perpendicular to their paths. Which of them will move in a circular path with higher frequency?
उत्तर
Radius of the orbit is given as r = `(mv)/(BQ)`
Time period = `(2pir)/v = (2pimv)/(vBQ) = (2pim)/(BQ)`
Frequency = `1/"Time period" = (BQ)/(2pim)`
As the frequency is inversely proportional to the mass of the particle, thus frequency of revolution of the electron is greater than that of proton because of less mass of electron.
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संबंधित प्रश्न
Draw a neat labelled diagram for the construction of 'cyclotron'
State the underlying principle of a cyclotron. Write briefly how this machine is used to accelerate charged particles to high energies
Deduce an expression for the frequency of revolution of a charged particle in a magnetic field and show that it is independent of velocity or energy of the particle.
If a watch-glass containing a small quantity of water is placed on two dissimilar magnetic poles, then water ______.
Draw a schematic sketch of a cyclotron. Explain clearly the role of crossed electric and magnetic field in accelerating the charge. Hence derive the expression for the kinetic energy acquired by the particles.
Consider a 10-cm long portion of a straight wire carrying a current of 10 A placed in a magnetic field of 0.1 T making an angle of 53° with the wire. What magnetic force does the wire experience?
(a) An electron moves along a circle of radius 1 m in a perpendicular magnetic field of strength 0.50 T. What would be its speed? Is it reasonable? (b) If a proton moves along a circle of the same radius in the same magnetic field, what would be its speed?
Assertion: The frequency of circular motion of a charged particle in cyclotron is independent of the mass of the particle.
Reason: Greater the mass of the particle less will be the frequency of the particle.
Which of the following is not correct about cyclotron?
Describe the motion of a charged particle in a cyclotron if the frequency of the radio frequency (rf) field were doubled.
