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प्रश्न
A toy is in the form of a cylinder with hemispherical ends. If the whole length of the toy is 90 cm and its diameter is 42 cm, then find the cost of painting the toy at the rate of 70 paise per sq cm.
उत्तर
We have,
the total height of the toy = 90 cm and
the radius of the toy, r= 42/2 = 21 cm
Also,the height of the toy, r=`42/2 = 21 "cm"`
Now , the total surface area of the toy =CSA of cylinder + 2 × CSA of a hemispher
`= 2pirh + 2 xx 2pir^2`
`= 2pir(h + 2r)`
`= 2xx22/7xx21xx(48+2xx21)`
`= 44xx3xx(48+42)`
`=44xx3xx90`
= 11880 cm2
So, the cost of painting the toy =`(11880xx70)/100 =Rs 83,16`
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Students found the shapes of the objects very interesting and they could easily relate them with mathematical shapes viz sphere, hemisphere, cylinder etc. |
Maths teacher who was accompanying the students asked the following questions:
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Statement A (Assertion): Total Surface area of the top is the sum of the curved surface area of the hemisphere and the curved surface area of the cone.
Statement R( Reason): Top is obtained by joining the plane surfaces of the hemisphere and cone together.