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A trust has 25 members. How many ways 3 officers can be selected? - Mathematics

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प्रश्न

A trust has 25 members. How many ways 3 officers can be selected?

बेरीज

उत्तर

Number of members in the trust = 25

The number of ways of selecting 3 officers from 25 members is

= 25C3 

= `(25!)/(3! xx (25 - 3)!)`

= `(25!)/(3! xx 22!)`

= `(25 xx 24 xx 23 xx 22!)/(3! xx 22!)`

= `(25 xx 24 xx 23)/(3 xx 2 xx 1)`

= 25 × 4 × 23

= 2300

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Combinations
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Combinatorics and Mathematical Induction - Exercise 4.3 [पृष्ठ १८६]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 4 Combinatorics and Mathematical Induction
Exercise 4.3 | Q 11. (i) | पृष्ठ १८६

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