Advertisements
Advertisements
प्रश्न
ABCD is a rhombus such that ∠ACB = 40º. Then ∠ADB is ______.
पर्याय
40º
45º
50º
60º
उत्तर
ABCD is a rhombus such that ∠ACB = 40º. Then ∠ADB is 50º.
Explanation:
Given, ABCD is a rhombus such that ∠ACB = 40º ⇒ ∠OCB = 40º
Since, AD || BC
∠DAC = ∠BCA = 40º ...[Alternate interior angles]
Also, ∠AOD = 90º ...[Diagonals of a rhombus are perpendicular to each other]
We know that, sum of all angles of a triangle ADO is 180º
∴ ∠ADO + ∠DOA + ∠OAD = 180º
∴ ∠ADO = 180º – (40º + 90º)
= 180º – 130º
= 50º
⇒ ∠ADB = 50º
APPEARS IN
संबंधित प्रश्न
In a quadrilateral, define of the following Sides.
In a quadrilateral, define of the following Adjacent sides .
Complete of the following, so as to make a true statement:
A quadrilateral has ....... sides.
In Fig. 16.19, ABCD is a quadrilateral.
How many pairs of adjacent sides are there?
In Fig. 16.19, ABCD is a quadrilateral.
How many pairs of adjacent angles are there?
ABCD is a trapezium in which AB || DC. M and N are the mid-points of AD and the respectively. If AB = 12 cm, MN = 14 cm, then CD =
Two adjacent angles of a parallelogram are 70° and 110° respectively. Find the other two angles of it.
The diagonals of a rhombus are 6 .cm and 8 cm. State the angle at which these diagonals intersect.
The three angles of a quadrilateral are 71°, 110°, 95°. Find its fourth angle.
In given figure, What is AC – EC?
