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प्रश्न
Add:
17a2b2 + 16c; 28c − 28a2b2
उत्तर १
(17a2b2 + 16c) + (28c − 28a2b2)
= 17a2b2 + 16c + 28c − 28a2b2
= (17a2b2 − 28a2b2) + (16c + 28c)
= −11a2b2 + 44c
उत्तर २
17a2b2 + 16c
+ (−28a2b2 + 28c)
−11a2b2 + 44c
संबंधित प्रश्न
Simplify combining like terms: 3a - 2b - ab - (a - b + ab) + 3ab + b - a
Subtract:
2a2 from − 7a2
Subtract:
\[\frac{3}{2}x - \frac{5}{4}y - \frac{7}{2}z \text { from }\frac{2}{3}x + \frac{3}{2}y - \frac{4}{3}z\]
Subtract the sum of 3l − 4m − 7n2 and 2l + 3m − 4n2 from the sum of 9l + 2m − 3n2 and − 3l + m + 4n2 .....
If \[x - \frac{1}{x} = 3,\] find the values of \[x^2 + \frac{1}{x^2}\] and \[x^4 + \frac{1}{x^4} .\]
The addition of – 7b and 2b is ____________
If x is a natural number, then x + 1 is its predecessor
Add:
3a(a – b + c), 2b(a – b + c)
Add the following expressions:
p2 – q + r, q2 – r + p and r2 – p + q
Add the following expressions:
x3y2 + x2y3 + 3y4 and x4 + 3x2y3 + 4y4
