Advertisements
Advertisements
प्रश्न
Add:
3a(a – b + c), 2b(a – b + c)
उत्तर
We have,
3a(a – b + c) + 2b(a – b + c)
= (3a2 – 3ab + 3ac) + (2ab – 2b2 + 2bc)
= 3a2 – 3ab + 2ab + 3ac + 2bc – 2b2 ...[Grouping like terms]
= 3a2 – ab + 3ac + 2bc – 2b2
APPEARS IN
संबंधित प्रश्न
Add the following:
2p2q2 − 3pq + 4, 5 + 7pq − 3p2q2
What should be taken away from 3x2 - 4y2 + 5xy + 20 to obtain - x2 - y2 + 6xy + 20?
From the sum of 3x - y + 11 and - y - 11, subtract 3x - y - 11.
Solve the following equation.
`4"x"+1/2=9/2`
The addition of – 7b and 2b is ____________
a(b + c) = a × ____ + a × _____.
The expression 13 + 90 is a ______.
Add the following expressions:
a2 + 3ab – bc, b2 + 3bc – ca and c2 + 3ca – ab
Add the following expressions:
`5/8p^4 + 2p^2 + 5/8; 1/8 - 17p + 9/8p^2` and `p^5 - p^3 + 7`
Add the following expressions:
t – t2 – t3 – 14; 15t3 + 13 + 9t – 8t2; 12t2 – 19 – 24t and 4t – 9t2 + 19t3
