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Add: 2p4 – 3p3 + p2 – 5p + 7, –3p4 – 7p3 – 3p2 – p – 12 - Mathematics

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प्रश्न

Add:

2p4 – 3p3 + p2 – 5p + 7, –3p4 – 7p3 – 3p2 – p – 12

बेरीज

उत्तर

We have,

(2p4 – 3p3 + p2 – 5p + 7) + (–3p4 – 7p3 – 3p2 – p – 12)

= 2p4 – 3p3 + p2 – 5p + 7 – 3p4 – 7p3 – 3p2 – p – 12

= (2p4 – 3p4) + (–3p3 – 7p3) + (p2 – 3p2) + (–5p – p) + (7 – 12)  ...[Grouping like terms]

= – p4 + (–10p3) + (–2p2) + (–6p) + (–5)

= – p4 – 10p3 – 2p2 – 6p – 5

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३०]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 8
पाठ 7 Algebraic Expression, Identities and Factorisation
Exercise | Q 81. (v) | पृष्ठ २३०
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