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प्रश्न
Add:
3a(2b + 5c), 3c(2a + 2b)
उत्तर
We have,
3a(2b + 5c) + 3c(2a + 2b)
= (6ab + 15ac) + (6ac + 6bc)
= 6ab + 15ac + 6ac + 6bc ...[Grouping like terms]
= 6ab + 21ac + 6bc
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संबंधित प्रश्न
What should be subtracted from 2a + 8b + 10 to get - 3a + 7b + 16?
Add the following algebraic expression:
\[\frac{11}{2}xy + \frac{12}{5}y + \frac{13}{7}x, - \frac{11}{2}y - \frac{12}{5}x - \frac{13}{7}xy\]
Subtract:
2a − b from 3a − 5b
Subtract:
\[\frac{3}{2}x - \frac{5}{4}y - \frac{7}{2}z \text { from }\frac{2}{3}x + \frac{3}{2}y - \frac{4}{3}z\]
Subtract:
\[x^2 y - \frac{4}{5}x y^2 + \frac{4}{3}xy \text { from } \frac{2}{3} x^2 y + \frac{3}{2}x y^2 - \frac{1}{3}xy\]
Multiply: \[\left( \frac{x}{7} + \frac{x^2}{2} \right)by\left( \frac{2}{5} + \frac{9x}{4} \right)\]
Add:
2a + 6b + 8c; 16a + 13c + 18b
Add:
5x2 – 3xy + 4y2 – 9, 7y2 + 5xy – 2x2 + 13
Add the following expressions:
p2 – q + r, q2 – r + p and r2 – p + q
Add the following expressions:
uv – vw, vw – wu and wu – uv
