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An Air-filled Parallel-plate Capacitor is to Be Constructed Which Can Store 12 µC of Charge When Operated at 1200 V. What Can Be the Minimum - Physics

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प्रश्न

An air-filled parallel-plate capacitor is to be constructed which can store 12 µC of charge when operated at 1200 V. What can be the minimum plate area of the capacitor? The dielectric strength of air is `3 xx 10^6  "Vm"^-1`

बेरीज

उत्तर

Charge that the capacitor can hold = 12 μC
Operating voltage = 1200 V

Breakdown strength, b = `3 xx 10^6  "Vm"^-1`

The separation between the plates of the capacitor is given by `d = V/b = 1200/(3 xx 10^6) = 4 xx 10^-4  "m"`

The capacitance of the capacitor is given by `C = Q/V = (12 xx 10^-6)/1200 = 10^-8  "F"`

The capacitance can be expressed in terms of the area of the plates (A) and the separation of the plates (d) as : `C = (∈_0A)/d = 10^-8  "F"`

Thus, the area of the plates is given by 

`A = (10^-8 xx (4 xx 10^-4))/(8.854 xx 10^-12) = 0.45  "m"^2`

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पाठ 9: Capacitors - Exercises [पृष्ठ १७०]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 9 Capacitors
Exercises | Q 64 | पृष्ठ १७०

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